KEAM 2013 Math Paper

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Question : 74 of 120

Marks: +1, -0

The point of intersection of the straight line

x−2

2

=

y−1

−3

=

z+2

1

with the plane x+3y−z+1=0 is equal to

(3,−1,1)
(−5,1,−1)
(2,0,3)
(5,−1,3)
(4,−2,−1)

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