KEAM 2013 Math Paper

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Question : 109 of 120

Marks: +1, -0

∫

4dx

x2√4−9x2

=

√4−9x2+C
−2
3
√4−9x2+C
−√4−9x2
x
+C
2
3
√4−9x2
x
+C
−3√4−9x2+C

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