KEAM 2013 Math Paper

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Question : 108 of 120

Marks: +1, -0

∫(27e9x+e12x)

1

3

dx is equal to

(
1
4
)(27+e3x)
1
3
+C
(
1
4
)(27+e3x)
2
3
+C
(
1
3
)(27+e3x)
4
3
+C
(
1
4
)(27+e3x)
4
3
+C
(
3
4
)(27+e3x)
4
3
+C

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