KCET 2016 Math Solved Paper

Given equation of plane: 5y+8=0
So,

→

N

=(0,5,0)
Equation of line passes through origin and is perpendicular to this plane is given by
‌

x

0

=‌

y

5

=‌

z

0

=λ
Foot of the perpendicular is found by intersection of line with plane. So,
x=0,y=5λ,z=0
Now, 25λ+8=0
⇒λ=

−8

25

Therefore, point is (0,

−8

5

,0)