The vector equation of the plane which is at a distance of 3/\sqrt14 from the origin and the normal from the origin is 2i^{\^} - 3 j^{\^} + k^{\^} is

Correct Answer is : →r.(2^i−3^j+^k)=3

r^{\to}.(2i^{\^} - 3 j^{\^} + k^{\^})=3

r^{\to}.(i^{\^} + j^{\^} + k^{\^})=9

KCET 2016 Math Solved Paper

Question : 56 of 60

Marks: +1, -0

The vector equation of the plane which is at a distance of

√14

from the origin and the normal from the origin is 2

−3

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