KCET 2014 Math Solved Paper

Given that,‌

x−2

3

=‌

y−3

4

=‌

z−4

5

→ (1)
So, direction ratio’s of line are 3, 4, 5.
Since, line and plane are parallel. So, normal to plane and line are perpendicular
Now, a1a2+b1b2+c1c2=0
for plane 2x+y−2z=0
Now, 3(2)+4(1)−2(5)=0
Hence, required equation is 2x+y−2z=0