KCET 2014 Math Solved Paper

Given that,‌

x

1

=‌

y

2

=‌

z

3

→ (1)
And point is P(2, 3, 4).
Now, direction ratio’s of normal to the plane is 1, 2, 3.
So, equation is 1x+2y+3z+d=0
It passes through point P(2, 3, 4)
So, 2+6+12+d=0
⇒d=−20
Therefore, required equation is x+2y+3z=20