Let \alpha, \beta, \gamma, be the three roots of the equation x^3+b x+c=0. If \beta \gamma=1=-\alpha, then b^3+2 c^3-3 \alpha^3-6 \beta^3-8 \gamma^3 is equal to [8-Apr-2023 shift 1]

JEE Mains 8-Apr-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 5 of 90

Marks: +1, -0

Let α,β,γ, be the three roots of the equation x3+bx+c=0. If βγ=1=−α, then b3+2c3−3α3−6β3−8γ3 is equal to

[8-Apr-2023 shift 1]

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