Let C(\alpha, \beta) be the circumcenter of the triangle formed by the lines 4 x+3 y=69 4 y-3 x=17 \text{ and } x+7 y=61 Then (\alpha-\beta)^2+\alpha+\beta is equal to [8-Apr-2023 shift 1]

JEE Mains 8-Apr-2023 Shift 1 Solved Paper

Section: Mathematics

Question : 4 of 90

Marks: +1, -0

Let C(α,β) be the circumcenter of the triangle formed by the lines
‌4x+3y=69
‌4y−3x=17‌ and ‌
‌x+7y=61
Then (α−β)2+α+β is equal to

[8-Apr-2023 shift 1]

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