JEE Mains 25-July-2022 Shift 1 Solved Paper

Section: Mathematics

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Question : 11 of 90

Marks: +1, -0

The general solution of the differential equation (x−y2)dx+y(5x+y2)dy=0 is:

[25-Jul-2022-Shift-1]

(y2+x)4=C|(y2+2x)3|
(y2+2x)4=C|(y2+x)3|
|(y2+x)3|=C(2y2+x)4
|(y2+2x)3|=C(2y2+x)4

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