The slope of the tangent to a curve C: y=y(x) at any point (x, y) on it is {2 {e}^{2 x}-6 {e}^{-x}+9}/{2+9 {e}^{-2 x}}. If C passes through the points (0, \frac{1}{2}+\frac{\pi}{2 \sqrt{2}) and (\alpha, \frac{1}{2} {e}^{2 \alpha}), then {e}^{\alpha} is equal to : [25-Jul-2022-Shift-1]

Correct Answer is : 3√2(3+√23−√2)

\frac{3}\sqrt{2}( {3+\sqrt{2}/{3-\sqrt{2})

\frac{1}\sqrt{2}( \sqrt{2}+1}/\sqrt{2}-1})

JEE Mains 25-July-2022 Shift 1 Solved Paper

Section: Mathematics

Question : 10 of 90

Marks: +1, -0

The slope of the tangent to a curve C:y=y(x) at any point (x,y) on it is ‌

2e2x−6e−x+9

2+9e−2x

. If C passes through the points (0,‌

+‌

2√2

) and (α,‌

e2α), then eα is equal to :

[25-Jul-2022-Shift-1]

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