JEE Mains 2020 Model Paper 3 New Pattern

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Question : 13 of 75

Marks: +1, -0

If f (x) = [

sin[x]

[x]

[x]≠0

0

[x]=0

, where [.] denotes G.I.F. then

limit

x→0

f (x) equals

1
0
- 1
does not exist

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