If a^{\to} = 3i^{\^}+3j^{\^}+\sqrt3 k^{\^} , b^{\to} = i^{\^}+k^{\^} , c^{\to} = \sqrt3 i^{\^}+\sqrt3 j^{\^} + \lambda k^{\^} are coplanar then the non zero vector b^{\to}\timesc^{\to} =

Correct Answer is : −√3^i+(√3−1)^j+√3^k

-\sqrt3 i^{\^}+(\sqrt3-1)j^{\^}+\sqrt3 k^{\^}

-\sqrt3 i^{\^}+(1-\sqrt3)j^{\^}+\sqrt3 k^{\^}

-\sqrt3 i^{\^}+(\sqrt3 - 1)j^{\^}-\sqrt3 k^{\^}

\sqrt3 i^{\^}+(\sqrt3 - 1)j^{\^} + \sqrt3 k^{\^}

JEE Mains 2020 Model Paper 3 New Pattern

Question : 12 of 75

Marks: +1, -0

→

= 3

+√3

→

= √3

+√3

+λ

are coplanar then the non zero vector

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