Solution of the equation 3\sqrt3 \sin^3 x+ \cos^3x + 3\sqrt3 sinx cosx = 1

Correct Answer is : x = (nπ+(−1)nπ6)−π6, n ∊ I

x = (n\pi + (-1)^n \pi/6) - \pi/6, n ∊ I

x = nπ + (-1)^n \pi/3, n ∊ I