JEE Mains 2020 Model Paper 1 New Pattern

Given system of homogeneous equations is tx+(t+1)y+(t−1)x=0,(t+1)x+ty+
(t+2)z=0,(t−1)x+(t−2)y+tz=0
For the given system of equations, we have
A=|

t	t+1	t−1
t+1	t	t+2
t−1	t−2	t

|
Solving for A , we get

⇒A=4t−2t−2−2t+2=0
The given matrix is a square matrix and we see A=0 , so it will always
have non-trivial solution for any value of t .