JEE Mains 04-Sep-2020 Shift 2 Solved Paper

Section: Physics

Question : 6 of 75

Marks: +1, -0

Find the bindng energy per nucleon for ‌50120Sn .
Mass of proton mP=1.00783 U, mass of neutron mn=1.00867 U and mass of tin nucleus mSn=119.902199 U. (take 1U=931MeV)

[4 Sep 2020 Shift 2]

8.5 MeV
7.5 MeV
8.0 MeV
9.0 MeV

Validate

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