The electric field of a plane electromagnetic wave is given by \overrightarrow{{E}}= {E}_{0} (\stackrel{\^}{{x}}+\stackrel{\^}{{y}}) \sin ( {kz}-\\omega{t}) Its magnetic field will be given by : [4 Sep 2020 Shift 2]

Correct Answer is : E0c(^−x+^y)sin(kz−ωt)

{{E}_{0}}/{ {c}}(\stackrel{\^}{{x}}-\stackrel{\^}{{y}}) \cos ( {kz}-\\omega{t})

{{E}_{0}}/{ {c}}(\stackrel{\^}{{-x}}+\stackrel{\^}{{y}}) \sin ( {kz}-\\omega{t})

{{E}_{0}}/{ {c}}(\stackrel{\^}{{ x}}-\stackrel{\^}{{y}}) \sin ( {kz}-\\omega{t})

{{E}_{0}}/{ {c}}(\stackrel{\^}{{ x}}+\stackrel{\^}{{y}}) \sin ( {kz}-\\omega{t})

JEE Mains 04-Sep-2020 Shift 2 Solved Paper

Section: Physics

Question : 5 of 75

Marks: +1, -0

The electric field of a plane electromagnetic wave is given by

→

=E0(

)‌sin(kz−ωt)
Its magnetic field will be given by :

[4 Sep 2020 Shift 2]

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