The line of shortest distance between the lines \frac{x-2}{0}=\frac{y-1}{1}=\frac{z}{1} and \frac{x-3}{2}=\frac{y-5}{2}=\frac{z-1}{1} makes an angle of \cos ^{-1}(\sqrt{\frac{2}{27}}) with the plane {P}: {a} x-y-z=0,(a>0). If the image of the point (1,1,-5) in the plane P is (\alpha, \beta, \gamma), then \alpha+\beta-\gamma is equal to [25-Jul-2022-Shift-1]

Three Dimensional Geometry Part 2

Section: Mathematics

Question : 9 of 100

Marks: +1, -0

The line of shortest distance between the lines ‌

x−2

=‌

y−1

=‌

and ‌

x−3

=‌

y−5

=‌

z−1

makes an angle of cos−1(√‌

) with the plane P:ax−y−z=0,(a>0). If the image of the point (1,1,−5) in the plane P is (α,β,γ), then α+β−γ is equal to

[25-Jul-2022-Shift-1]

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