Three Dimensional Geometry Part 2

Let point S(a, b, c)
Then,

a−1

2

=

b−3

−1

=

c−4

1

=

−2(2−3+4+3)

4+1+1

=−2
⇒ a = − 3, b = 5, c = 2
∴ S (− 3, 5, 2)
and point R(3, 5, γ) lies on the plane 2x − y + z + 3 = 0
⇒ 6 − 5 + γ + 3 = 0
⇒ γ = − 4
∴ R (3, 5, − 4)
Now, SR2=62+02+(6)2
=36+0+36=72