The square of the distance of the point of intersection of the line \frac{x-1}{2}=\frac{y-2}{3}=\frac{z+1}{6} and the plane 2 x-y+z=6 from the point (-1,-1,2) is [31 Aug 2021 Shift 1]

Three Dimensional Geometry Part 2

Section: Mathematics

Question : 44 of 100

Marks: +1, -0

The square of the distance of the point of intersection of the line

x−1

y−2

z+1

and the plane 2x−y+z=6 from the point (−1,−1,2) is

[31 Aug 2021 Shift 1]

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