Let y=y(x) be the solution of the differential equation (1+x^2) \frac{d y}{d x}+y=e^{\tan ^{-1} x}, y(1)=0. Then y(0) is [6 Apr 2024 Shift 1]

Correct Answer is : 12(1−eπ∕2)

\frac{1}{4} ( {\e}^{\pi \/ 2}-1)

\frac{1}{2} ( {\e}^{\pi \/ 2}-1)

Differential Equations Part 2

Section: Mathematics

Question : 8 of 100

Marks: +1, -0

Let y=y(x) be the solution of the differential equation (1+x2)‌

+y=etan−1x,y(1)=0. Then y(0) is

[6 Apr 2024 Shift 1]

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