Differential Equations Part 2
© examsiri.com
Question : 7 of 100
Marks:
+1,
-0
Let y = y ( x ) be the solution of the differential equation ( 2 x log e x )
+ 2 y =
log e x , x > 0 and y ( e − 1 ) = 0 . Then, y ( e ) is equal to
[6 Apr 2024 Shift 1]
Go to Question: