Differential Equations Part 1

Section: Mathematics

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Question : 22 of 100

Marks: +1, -0

Let y=y(x) be the solution of the differential equation ex√1−y2dx+(

y

x

)dy=0, y(1)=−1.Then the value of (y(3))2 is equal to:

[20 Jul 2021 Shift 1]

1−4e3
1−4e6
1+4e3
1+4e6

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