Let y=y(x) be the solution of the differential equation x \tan (\frac{y}{x}) d y=(y \tan (\frac{y}{x})-x) d x-1 \\leq {x} \\leq 1, {y}(\frac{1}{2})=\frac{\\pi}{6} . Then the area of the region bounded by the curves x=0, x={1}/{\\sqrt{2} and y=y(x) in the upper half plane is: [20 Jul 2021 Shift 1]

Differential Equations Part 1

Section: Mathematics

Question : 21 of 100

Marks: +1, -0

Let y=y(x) be the solution of the differential equation x‌tan(

)‌d‌y=(y‌tan(

)−x)dx−1≤x≤1,y(

. Then the area of the region bounded by the curves x=0,x=

√2

and y=y(x) in the upper half plane is:

[20 Jul 2021 Shift 1]

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