JEE Main 9 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 34 of 90

Marks: +1, -0

For each x ∊ R, let [x] be the greatest integer lessthan or equal to x. Then

lim

x→0−

x([x]+|x|)sin[x]

|x|

is equal to

[9 Jan 2019 Shift 2]

- sin 1
0
1
sin 1

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