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Question : 18 of 90
Marks:
+1,
-0
Solution:
‌=−‌⇒(x,y,z)=(α−5,1,−2)‌⇒x=α−5,y=1,z=−2 . . . (1)
Area of
∆=5√6 (given)
‌‌|×|=5√6‌||=10√6‌⇒|−10−(−2α−2x)+(α−4x)|=10√6‌⇒(2α+2α−10)2+(α−4α+20)2=500‌⇒(4α−10)2+(20−3α)2=500‌⇒25α2−80α−120α=0‌⇒α(25α−200)=0‌⇒α=8(‌ given ‌α‌ is +ve number) ‌‌⇒x=α−5=3‌||2=x2+y2+z2‌=9+1+4‌=14
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