JEE Main 9 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 17 of 90

Marks: +1, -0

The solution of the differential equation (x2+y2)‌dx−5xydy=0,y(1)=0, is :

[9 Apr 2024 Shift 1]

|x2−4y2|5=x2
|x2−2y2|6=x
|x2−4y2|6=x
|x2−2y2|5=x2

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