JEE Main 7 Apr 2025 Shift 1 Paper

Section: Mathematics

Question : 5 of 75

Marks: +1, -0

Let y=y(x) be the solution curve of the differential equation x(x2+ex)dy+(ex(x−2)y−x3)‌dx=0, x>0, passing through the point (1,0). Then y(2) is equal to

[7 Apr 2025 Shift 1]

‌
2
2+e2
‌
4
4−e2
‌
2
2−e2
‌
4
4+e2

Validate

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