JEE Main 7 Apr 2025 Shift 1 Paper
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Question : 4 of 75
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Let x = − 1 and x = 2 be the critical points of the function f ( x ) = x 3 + a x 2 + b log e | x | + 1 , x ≠0 . Let m and M respectively be the absolute minimum and the absolute maximum values of f in the interval [ − 2 , −
] . Then | M + m | is equal to (Take log 2 = 0.7):
[7 Apr 2025 Shift 1]
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