JEE Main 29 June 2022 Shift 1 Solved Paper

Section: Mathematics
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Question : 16 of 90
 
Marks: +1, -0
If the constant term in the expansion of
(3x3−2x2+‌
5
x5
)
10
is 2k.I, where I is an odd integer, then the value of k is equal to:
[29-Jun-2022-Shift-1]
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