The domain of the function \cos ^{-1}( {2 \sin ^{-1}(\frac{1}{4 x^2-1})}/{\pi}) is : [29-Jun-2022-Shift-1]

Correct Answer is : (−∞,−1√2]∪[1√2,∞)∪{0}

R-\{-\frac{1}{2}, \frac{1}{2}\}

(-\infty,-1] \cup[1, \infty) \cup\{0\}

(-\infty, \frac{-1}{2}) \cup(\frac{1}{2}, \infty) \cup\{0\}

(-\infty, \frac{-1}\sqrt{2}] \cup[\frac{1}\sqrt{2}, \infty) \cup\{0\}

JEE Main 29 June 2022 Shift 1 Solved Paper

Section: Mathematics

Question : 15 of 90

Marks: +1, -0

The domain of the function cos−1(‌

2sin−1(

4x2−1

)

) is :

[29-Jun-2022-Shift-1]

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