JEE Main 28 Jan 2026 Shift 2 Paper Solved Paper
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Question : 8 of 75
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Let f ( x ) = ∫
, be such that f ( 0 ) = − 26 + 24 log e ( 2 ) . If f ( 1 ) = a + b log e ( 3 ) , where a , b ∈ Z , then a + b is equal to:
[28 Jan 2026 Shift 2]
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