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JEE Main 28 Jan 2026 Shift 2 Paper Solved Paper

Section: Mathematics
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Question : 7 of 75
 
Marks: +1, -0
Let P be a point in the plane of the vectors
→
AB
=3
∧
i
+
∧
j
−
∧
k
 and
→
AC
=
∧
i
−
∧
j
+3
∧
k
 such that P is equidistant from the lines AB and AC . If |
→
AP
|=‌
√5
2
, then the area of the triangle ABP is :
[28 Jan 2026 Shift 2]
Validate
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