JEE Main 26 June 2022 Shift 2 Solved Paper
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Question : 9 of 90
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If y = y ( x ) is the solution of the differential equation x
+ 2 y = x e x , y ( 1 ) = 0 then the local maximum value of the function z ( x ) = x 2 y ( x ) − e x , x ∈ R is :
[26-Jun-2022-Shift-2]
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