JEE Main 26 June 2022 Shift 2 Solved Paper

Section: Mathematics
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Question : 10 of 90
 
Marks: +1, -0
If the solution of the differential equation
‌
dy
dx
+ex(x2−2)y
=(x2−2x)(x2−2)e2x
satisfies y(0)=0, then the value of y(2) is__
[26-Jun-2022-Shift-2]
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