JEE Main 26 Feb 2021 Shift 1 Solved Paper

Given, mass of box, m=2kg
Force, F=20

∧

i

+10

∧

j

N
Initial speed of box, u=0ms−1
Time, t=10s
Let acceleration of box is a and displacement along X-axis after 10s is Sx.
As, ‌‌F=ma
⇒‌‌a=F∕m=‌20

∧

i

+10

∧ j

2

=(10

∧

i

+5‌

∧

j

)‌ms−2
By second equation of motion along X-axis,
‌sx=uxt+‌

1

2

axt2
‌sx=0+‌

1

2

×10×(10)2=500m
Hence, displacement along X-axis after 10s is 500m.