JEE Main 26 Feb 2021 Shift 1 Solved Paper
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Question : 24 of 90
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A radiation is emitted by 1000 W bulb and it generates an electric field and magnetic field at P , placed at a distance of 2 m . The efficiency of the bulb is 1.25 % . The value of peak electric field at P is x × 10 − 1 V ∕ m . Value of x is .......... (Rounded-off to the nearest integer) [Take, ε 0 = 8.85 × 10 − 12 C 2 N − 1 m − 2 , c = 3 × 10 8 m s − 1 ]
[26 Feb 2021 Shift 1]
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