Let the eccentricity of the hyperbola \frac{x^2}{a^2}-\frac{y^2}{b^2}=1 be \frac{5}{4}. If the equation of the normal at the point (\frac{8}\sqrt{5}, \frac{12}{5}) on the hyperbola is 8 \sqrt{5} x+\beta y=\lambda, then \lambda-\beta is equal to____ [25-Jun-2022-Shift-2]

JEE Main 25 June 2022 Shift 2 Solved Paper

Section: Mathematics

Question : 29 of 90

Marks: +1, -0

Let the eccentricity of the hyperbola ‌

−‌

=1 be ‌

. If the equation of the normal at the point (‌

√5

,‌

) on the hyperbola is 8√5x+βy=λ, then λ−β is equal to____

[25-Jun-2022-Shift-2]

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