JEE Main 25 June 2022 Shift 2 Solved Paper

Section: Mathematics

Question : 28 of 90

Marks: +1, -0

Let f(x)=|(x−1)(x2−2x−3)|+x−3,x∈R. If m and M are respectively the number of points of local minimum and local maximum of f in the interval (0,4), then m+M is equal to____

[25-Jun-2022-Shift-2]

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(x−3)(x2)	3≤x≤4
(x−3)(2−x2)	1≤x<3
(x−3)(x2)	0<x<1.

3x2−6x	3<x<4
−3x2+6x+2	1<x<3
3x2−6x	0<x<1.