JEE Main 17 March 2021 Shift 2 Solved Paper

Given
Height of satellite from planet's surface, h=11R
So, the total distance from the centre of planet =11R+R=12R
Time period of planet =24h
Similarly, the total distance of second satellite from the centre of planet =2R+R=3R
Using the Kepler's law
T2∝R3
⇒‌‌(‌

T1

T2

)=(‌

R1

R2

)3∕2
Substituting the values in the above equation, we get
(‌

24

T

)=(‌

12R

3R

)3∕2
∴ The time period of another satellite is 3h.