JEE Main 17 March 2021 Shift 2 Solved Paper

Given, The volumetric strain is ‌

∆V

V

=1.36%
The depth beneath the water surface, h=2km
The pressure inside the water surface up to 2km,
p=ρgh
Substituting the values in the above equation, we get
p=1000×9.81×2000
p=19.62×106Pa
The bulk modulus of the object,
β=‌

p

∆V V

Substituting the values in the above equation, we get
β=‌

19.62×106

1.36 100

β=1.44×109N∕m2
Hence, the ratio of the hydraulic stress to the corresponding hydraulic strain will be 1.44×109N∕m2.