JEE Main 16 March 2021 Shift 2 Solved Paper

Section: Mathematics
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Question : 76 of 90
 
Marks: +1, -0
Let f:S→S, where S=(0,∞) be a twice differentiable function, such that f(x+1)=x‌‌f(x). If g:S→R be defined as g(x)=logef(x), then the value of g′′(5)−g′′(1)| is equal to
[16 Mar 2021 Shift 2]
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