Let f be a real valued function, defined on R-\{-1,1\} and given by f(x)=3 \log _{e}|\frac{x-1}{x+1}|-\frac{2}{x-1} Then, in which of the following intervals, function f(x) is increasing? [16 Mar 2021 Shift 2]

Correct Answer is : (−∞,−1)∪([12,∞)−{1})

(-\infty,-1) \cup([\frac{1}{2}, \infty)-\{1\})

JEE Main 16 March 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 75 of 90

Marks: +1, -0

Let f be a real valued function, defined on R−{−1,1} and given by f(x)=3loge|‌

x−1

x+1

|−‌

x−1

Then, in which of the following intervals, function f(x) is increasing?

[16 Mar 2021 Shift 2]

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