JEE Main 12 Apr 2019 Paper 2 Solved Paper
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Question : 26 of 90
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An electron, moving along the x a x i s with an initial energy of 100 e V , enters a region of magnetic field
= ( 1.5 × 10 − 3 T )
at S (See figure). The field extends between x = 0 and x = 2 c m . The electron is detected at the point Q on a screen placed 8 cm away from the point S. The distance d between P and Q (on the screen) is: (electron’s charge 1.6 × 10 − 19 C , mass of electron 9.1 × 10 − 31 k g )
[12 Apr 2019 Shift 2]
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