A plane electromagnetic wave having a frequency v = 23.9 GHz propagates along the positive z-direction in free space. The peak value of the electric field is 60 {V /m. which among the following is the acceptable magnetic field component in the electromagnetic wave ? [12 Apr 2019 Shift 2]

Correct Answer is : →B=2×10−7sin (0.5×103z−1.5×1011t )^i

B^{\to}=2 \times 10^{-7} \sin (0.5 \\times10^{3} {z}-1.5 \times 10^{11} t ) i^{\^}

B^{\to}=2 \times 10^{-7} \sin (0.5 \\times10^{2} {x}-1.5 \times 10^{11} t ) i^{\^}

B^{\to}=2 \times 10^{-7} \sin (0.5 \\times10 ^{3}z-1.5 \times 10^{11} t ) i^{\^}

B^{\to}=60 \sin (0.5 \\times10 ^{3}z-1.5 \times 10^{11} t ) i^{\^}

JEE Main 12 Apr 2019 Paper 2 Solved Paper

Section: Physics

Question : 25 of 90

Marks: +1, -0

A plane electromagnetic wave having a frequency v=23.9GHz propagates along the positive z-direction in free space. The peak value of the electric field is 60

. which among the following is the acceptable magnetic field component in the electromagnetic wave ?

[12 Apr 2019 Shift 2]

→
B
=2×10−7‌sin‌ (0.5×103z−1.5×1011t )‌
^
i
→
B
=2×10−7‌sin‌ (0.5×102x−1.5×1011t )‌
^
i
→
B
=2×10−7‌sin‌ (0.5×103z−1.5×1011t )‌
^
i
→
B
=60‌sin‌ (0.5×103z−1.5×1011t )‌
^
i

Validate

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