JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 5 of 90

Marks: +1, -0

A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and an amplitude of 10–2 m. The relative change in the angular frequency of the pendulum is best given by :-

[11 Jan 2019 Shift 2]

10–3 rad/s
10–1 rad/s
1 rad/s
10–5 rad/s

Validate

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