JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 4 of 90

Marks: +1, -0

An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10–29 C.m. What is the potential energy of the electric dipole ?

[11 Jan 2019 Shift 2]

– 9 × 10–20 J
– 7 × 10–27 J
– 10 × 10–29 J
– 20 × 10–18 J

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