JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 11 of 90

Marks: +1, -0

A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then :-

[11 Jan 2019 Shift 2]

K2 =
K1
4
K2 =
K1
2
K2 = 2K1
K2 = K1

Validate

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