JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 10 of 90

Marks: +1, -0

A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space ∊0 = 9 × 10–12 SI units, Speed of light c = 3 × 108 m/s]:-

[11 Jan 2019 Shift 2]

1 kV/m
2 kV/m
1.4 kV/m
0.7 kV/m

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