JEE Main 10 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 24 of 90

Marks: +1, -0

A thin disc of mass M and radius R has mass per unit area σ(r)=kr2 where r is the distance from its center . Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is :

[10 Apr 2019 Shift 1]

MR2
3
2MR2
3
MR2
2
MR2
6

Validate

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